Y=3x^2+12x+15

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Solution for Y=3x^2+12x+15 equation: 



=3Y^2+12Y+15

We move all terms to the left:

-(3Y^2+12Y+15)=0

We get rid of parentheses

-3Y^2-12Y-15=0

a = -3; b = -12; c = -15;
Δ = b2-4ac
Δ = -122-4·(-3)·(-15)
Δ = -36
Delta is less than zero, so there is no solution for the equation

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